A ball is thrown from a top of a tower with an initial velocity of 10m/s at an angle of 30° with the horizontal. If it hits the ground at a distance of 17.3m from the base of te tower, Calculate the height of the tower.
The Correct Answer is 10 m.
The Solution
When we draw the diagram of the motion we get a right angled triangle.
We have an angle of 30° and a base of 17.3m.
We will use trigonometric ratios to solve this.
We will use tan.
Tan Opposite / adjacent =
Tan 30° = h / 17.3
h = Tan 30 × 17.3
h = 0.5774 x 17.3 = 10 m
So, height of tower, h=10 m.