**A ball is thrown from a top of a tower with an initial velocity of 10m/s at an angle of 30° with the horizontal. If it hits the ground at a distance of 17.3m from the base of te tower, Calculate the height of the tower.**

**The Correct Answer is**

**10 m**.

__The Solution__

When we draw the diagram of the motion we get a right angled triangle.

We have an angle of 30° and a base of 17.3m.

We will use trigonometric ratios to solve this.

We will use tan.

Tan Opposite / adjacent =

Tan 30° = h / 17.3

h = Tan 30 × 17.3

h = 0.5774 x 17.3 = 10 m

So, height of tower, h=10 m.